題目
Given a valid (IPv4) IP address, return a defanged version of that IP address.
A defanged IP address replaces every period “.” with “[.]”.
## Example 1:
Input: address = "1.1.1.1"
Output: "1[.]1[.]1[.]1"
Example 2:
Input: address = "255.100.50.0"
Output: "255[.]100[.]50[.]0"
- 題意: 將字串.替換成[.]就好了
解法
import (
"strings"
)
func defangIPaddr(address string) string {
return strings.Replace(address, ".", "[.]", -1)
}
- 加個測試，看看結果是不是如預期
import (
"github.com/stretchr/testify/assert"
"testing"
)
func Test_defangIPaddr(t *testing.T) {
address := "1.1.1.1"
assert.Equal(t, "1[.]1[.]1[.]1", defangIPaddr(address))
}